如何设置快递websocket服务器的路由？

我有一个类似于这个的设置：

var WebSocketServer = require("ws").Server, express = require("express"), http = require("http"), app = express(), server = http.createServer(app); app.post("/login", login); app.get("/...", callSomething); // ... server.listen(8000); var wss = new WebSocketServer({server: server}); wss.on("connection", function(ws){ // ... }); 

我想把WebSocketServer放在特定的path下，例如"...com/whatever" 。 问题是如何设置path？ 可能吗？

Answer 1

您将需要使用path选项：

 var wss = new WebSocketServer({server: server, path: "/hereIsWS"}); 

请参阅完整的文档

Answer 2

使用express-ws： https ： //www.npmjs.com/package/express-ws

安装：

 npm i express-ws -S 

代码示例：

 const express = require('express') const enableWs = require('express-ws') const app = express() enableWs(app) app.ws('/echo', (ws, req) => { ws.on('message', msg => { ws.send(msg) }) ws.on('close', () => { console.log('WebSocket was closed') }) }) 

Answer 3

接受的答案不再有效，并会抛出Frame Header Invalid错误。 请求＃885 。

WSpath被删除，如Lpinca所说：

这里的问题是，每个WebSocketServer都会为HTTP服务器上的升级事件添加一个新的侦听器，并且在发出该事件时，会在所有服务器上调用handleUpgrade。

这是周围的工作：

 const wss1 = new WebSocket.Server({ noServer: true }); const wss2 = new WebSocket.Server({ noServer: true }); const server = http.createServer(); server.on('upgrade', (request, socket, head) => { const pathname = url.parse(request.url).pathname; if (pathname === '/foo') { wss1.handleUpgrade(request, socket, head, (ws) => { wss1.emit('connection', ws); }); } else if (pathname === '/bar') { wss2.handleUpgrade(request, socket, head, (ws) => { wss2.emit('connection', ws); }); } else { socket.destroy(); } });