urlpath包含未转义的字符

我得到以下错误。我知道我需要逃脱几个字符，但有没有更好的方法来做到这一点？

我的pathvariables有一些错误

getNearByUsers(latlong) { return http.get({ host: 'search-vegme-user-7l3rylms73566frh4hwxblekn4.us-east-1.cloudsearch.amazonaws.com', path: '/2013-01-01/search?q=nikhil&expr.distance=haversin(35.621966,-120.686706,latlong.latitude,latlong.longitude)&sort=distance asc&return=distance,displayname,profileimageurl' }, function(response) { // Continuously update stream with data var body = ''; response.on('data', function(d) { body += d; }); response.on('end', function() { // Data reception is done, do whatever with it! var parsed = JSON.parse(body); console.log(parsed); }); }); } "errors": [ { "message": "Request path contains unescaped characters.", "originalError": {} } ] 

Answer 1

你需要使用encodeURIComponent（） 。

 var value = "haversin(35.621966,-120.686706,latlong.latitude,latlong.longitude)"; value = encodeURIComponent(value); console.log(value); //"haversin(35.621966%2C-120.686706%2Clatlong.latitude%2Clatlong.longitude)" 

改进的解决scheme： Javascript对象的查询string编码

 serialize = function(obj) { var str = []; for(var p in obj) if (obj.hasOwnProperty(p)) { str.push(encodeURIComponent(p) + "=" + encodeURIComponent(obj[p])); } return str.join("&"); } console.log("/2013-01-01/search?" + serialize({ 'q': "nikhil", 'expr.distance': "haversin(35.621966,-120.686706,latlong.latitude,latlong.longitude)", 'sort': "distance asc", 'return': "distance,displayname,profileimageurl" }));