TypeScript导入与ES6对象解构
随着TSimport,我相信我可以做到这一点:
import {foo as bar} from 'foo';
与JS或TypeScript的ES6对象解构 – 有没有办法以同样的方式重命名“导入的值”?
例如,
const {longVarName as lvn} = x.bar;
使用Jaromanda Xbuild议的解决scheme:
const {longVarName: lvn} = x.bar;
事实上,你可以做更多的事情:
多个variables
var {p: foo, q: bar} = o;
默认值:
var {a = 10, b = 5} = {a: 3};
嵌套对象:
const x = {a: {b: {c: 10}}}; const {a: {b: {c: ten}}} = x; // ten === 10
有关更多信息,请参阅https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Operators/Destructuring_assignment