在Sequelize中使用JOIN

提示如何在Sequelize中使用JOIN？ 我有以下代码：

db.User.findAll({ attributes: ['id'], where: {vipEnd: {lt: expiresVip}, vip: true}, limit: 100, order: 'id' }).then(function(users) { 

4，看起来像这样：

 SELECT "vkId" AS "id" FROM "user" AS "user" WHERE "user"."vipEnd" < 1469699683 --expiresVip AND "user"."vip" = true ORDER BY id LIMIT '100'; 

如何实现这样的结果？

 SELECT "vkId" AS "id" FROM "user" AS "user" LEFT JOIN "notification" ON "notification"."userId" = "user"."vkId" WHERE "user"."vipEnd" < 1469699683 AND "user"."vip" = true AND "notification"."type" = 4 AND "notification"."expiresVipDate" < 1469699683 ORDER BY id LIMIT '100'; 

谢谢！

Answer 1

您需要定义模型的关联。 例如： db.User.hasMany(db.Notification, {foreignKey: 'UserId'}); 使用属性包括在sequelize中：

 db.User.findAll({ include: [{ model: db.Notification, required: true//true INNER JOIN, false LEFT OUTER JOIN - default LEFT OUTER JOIN }]}).then(function(user) {}, function(err) { res.json(err, 400);}); 

您应该在这里查阅http://docs.sequelizejs.com/en/latest/docs/associations/