Sequelize生成错误的查询？ sequelize-auto-ts和sequelize

我正在使用Typescript，NodeJS和sequelize-auto-ts来生成模型。 我想要放置一个包含find查询的两个模型给了我错误的结果，而这又是由于错误的查询被解雇了。 这里有两个模型。

rewardcodes = <types.rewardcodesModel> sequelize.define<types.rewardcodeInstance, types.rewardcodePojo>('rewardcodes', { 'rewardid': { type: 'number', primaryKey: true, autoIncrement: true }, 'code':'string', 'amount':'string' }, { timestamps: false, classMethods: { getrewardcode:(rewardcode:types.rewardcodePojo) => { var where:{[key:string]:any} = {}; if (rewardcode['rewardid'] !== undefined) { where['rewardid'] = rewardcode['rewardid']} if (rewardcode['code'] !== undefined) { where['code'] = rewardcode['code']} if (rewardcode['amount'] !== undefined) { where['amount'] = rewardcode['amount']} return this.find({where: where}); } } }); 

和

 userfreecredits = <types.userfreecreditsModel> sequelize.define<types.userfreecreditInstance, types.userfreecreditPojo>('userfreecredits', { 'id': { type: 'number', primaryKey: true, autoIncrement: true }, 'userid': { type: 'number', references:user }, 'rewardid': {type: 'number',references: rewardcodes}, 'isexpired':'Buffer', 'isused':'Buffer', 'isactive':'Buffer', 'expireydate':'Date' }, { timestamps: false, classMethods: { getuserfreecredit:(userfreecredit:types.userfreecreditPojo) => { var where:{[key:string]:any} = {}; if (userfreecredit['id'] !== undefined) { where['id'] = userfreecredit['id']} if (userfreecredit['userid'] !== undefined) { where['userid'] = userfreecredit['userid']} if (userfreecredit['rewardid'] !== undefined) { where['rewardid'] = userfreecredit['rewardid']} if (userfreecredit['isexpired'] !== undefined) { where['isexpired'] = userfreecredit['isexpired']} if (userfreecredit['isused'] !== undefined) { where['isused'] = userfreecredit['isused']} if (userfreecredit['isactive'] !== undefined) { where['isactive'] = userfreecredit['isactive']} if (userfreecredit['expireydate'] !== undefined) { where['expireydate'] = userfreecredit['expireydate']} return this.find({where: where}); } } }); 

我正在做的db调用如下;

  var association = <sequelize.AssociationOptions>{}; association.foreignKey = "rewardid"; models.userfreecredits.hasOne(models.rewardcodes,association); models.rewardcodes.hasMany(models.userfreecredits); var findOptions = <sequelize.FindOptions>{}; findOptions.where = { userid: userId, isexpired: false, isused: false, isactive: true, expireydate: { gte: new Date() } }; findOptions.include = models.rewardcodes; return models.userfreecredits.find(findOptions).complete((err: Error, credits: types.userfreecreditInstance) => { return credits; }); 

但是从上面生成的查询是错误的，并说userfreecredit.id = rewardcodes.id

 SELECT `userfreecredits`.*, `rewardcode`.`rewardid` AS `rewardcode.rewardid`, `rewardcode`.`code` AS `rewardcode.code`, `rewardcode`.`amount` AS `rewardcode.amount` FROM `userfreecredits` LEFT OUTER JOIN `rewardcodes` AS `rewardcode` ON `userfreecredits`.`id` = `rewardcode`.`rewardid` WHERE `userfreecredits`.`userid`='1' AND `userfreecredits`.`isexpired`=false AND `userfreecredits`.`isused`=false AND `userfreecredits`.`isactive`=true AND`userfreecredits`.`expireydate` >= '2014-08-29 21:49:08' LIMIT 1; 

请帮我指出我做错了什么或失踪。

Answer 1

所以我发现我的错误，而不是hasOne我不得不使用belongsTo，它的工作。参考文档http://sequelizejs.com/docs/latest给了我一些道理，但过了一段时间gist.github.com/sdepold/1757695