Postgres + Sequelize:如何读取函数结果?

我有一个函数payment_summary()如下:

 CREATE OR REPLACE FUNCTION payment_summary() RETURNS SETOF PAYMENT_SUMMARY_TYPE LANGUAGE plpgsql AS $$ DECLARE payment_sum payment_summary_type%ROWTYPE; BEGIN FOR payment_sum IN SELECT pay.application_no, project.title, pay.payment_rec, customer.cust_name, project.estimated_cost, (project.estimated_cost - pay.payment_rec) AS outstanding_amt FROM project INNER JOIN customer ON project.customer_cust_id = customer.cust_id INNER JOIN (SELECT project.application_no, sum(payment.amount) AS payment_rec FROM payment INNER JOIN project ON payment.project_id = project.project_id WHERE payment.drcr_flg = 'Cr' GROUP BY project.application_no) AS pay ON pay.application_no = project.application_no LOOP RETURN NEXT payment_sum; END LOOP; END; $$; 

PAYMENT_SUMMARY_TYPE被定义为:

 CREATE TYPE PAYMENT_SUMMARY_TYPE AS ( application_no VARCHAR(150), title VARCHAR(500), payment_rec INTEGER, customer_name VARCHAR(500), estimated_cost INTEGER, outstanding_amt INTEGER ); 

使用下面的代码来执行该函数并获取结果:

 sequelize.query('SELECT payment_summary()').then(function(data) { res.json(data); }); 

作为回应得到下面

 [ [ { "payment_summary": "(716,\"C1\",100000,\"C1 - city\",0,-100000)" }, { "payment_summary": "(716,\"C2\",100000,\"C2 - city\",0,-100000)" } ], { "command": "SELECT", "rowCount": 2, "oid": null, "rows": [ { "payment_summary": "(716,\"C1\",100000,\"C1 - city\",0,-100000)" }, { "payment_summary": "(716,\"C2\",100000,\"C2 - city\",0,-100000)" } ], "fields": [ { "name": "payment_summary", "tableID": 0, "columnID": 0, "dataTypeID": 17453, "dataTypeSize": -1, "dataTypeModifier": -1, "format": "text" } ], "_parsers": [ null ], "rowAsArray": false } ] 

我需要以下格式的回应:

 [ { application_no: 716, title: "C1", payment_rec : 100000, customer_name : "C1 - city" estimated_cost : 0 outstanding_amt : -100000 }, { application_no: 717, title: "C2", payment_rec : 100000, customer_name : "C2 - city" estimated_cost : 0 outstanding_amt : -100000 } ] 

我如何读取/转换所需格式的响应?