如何在Node.js的Express.js GET GET多个variables？
我试图从HTML页面获取表单数据到Node Js服务器。
我的html文件是index.html
<body> <nav> <ul> <li> <a href="#" class="button add">Add Product</a> <div class="dialog" style="display:none"> <div class="title">Add Product</div> <form action="" method="get"> <input id = "name" name="name" type="text" placeholder="Product Name"/> <input name="code" type="text" placeholder="Product Code"/> <input name="category" type="text" placeholder=" Category"/> <input name="brand" type="text" placeholder="Brand"/> <input type="submit" value="Ok"/> </form> </div> </li> <li class="radio"> <a href="#" class="button active"></a> <a href="#" class="button"></a> <a href="#" class="button"></a> </li> </ul> </div> </nav> <p></p> <script src='http://cdnjs.cloudflare.com/ajax/libs/jquery/2.1.3/jquery.min.js'></script> <script src="js/index.js"></script> </body> 提交表单后，服务器不会执行任何操作，只需获取具有所有详细信息的url
而我的服务器是server.js
var express = require("express"), app = express(), bodyParser = require('body-parser'), errorHandler = require('errorhandler'), methodOverride = require('method-override'), hostname = process.env.HOSTNAME || 'localhost', port = parseInt(process.env.PORT, 10) || 4004, publicDir = process.argv[2] || __dirname + '/public'; var exec = require('child_process').exec; var fs = require('fs'); //Show homepage app.get("/", function (req, res) { res.redirect("/index.html"); console.log("shubh "); }); app.get("/index/", function (req, res) { res.redirect("/index.html"); console.log("shubham "); }); app.get("/index/:name", function (req, res){ console.log("shubham batra"); var keyword = req.query.code; console.log(keyword); //res.send('You sent the name "' + req.body.name + '".'); console.log(res.body); }); app.use(errorHandler({ dumpExceptions: true, showStack: true })); //Search page app.use(methodOverride()); app.use(bodyParser.json()); app.use(bodyParser.urlencoded({ extended: true })); app.use(express.static(publicDir)); app.use(errorHandler({ dumpExceptions: true, showStack: true })); console.log("Server showing %s listening at http://%s:%s", publicDir, hostname, port); app.listen(port);
您的表单操作是“”，因此表单创build的URL将是/？name = xxx＆code = yyy等
从你的路由，你似乎期待的URLforms是/ xxx？code = yyy。
使你的表单行动“/search”，并添加以下JS。
app.get("/search", function (req, res){ console.log("shubham batra"); var keyword = req.query.code; console.log(keyword); //res.send('You sent the name "' + req.query.name + '".'); });
当您发出请求时，request.body将不会被设置。
你可以像你想要的那样使用多个：
var code = req.query.code; var category = req.query.category; var brand = req.query.brand;
req.query如果它的GET请求和req.body如果它的POST。
改变app.get("/index/:name", function (req, res){
到app.get("/index/:name?", function (req, res){
你的路线将匹配/ index /和/ index / anyname路线
并将表单动作更改为"/"或类似"/action"