MySQLjoin，ORDER BY RAND（）然后sortingASC（最好使用Sequelize）
我想帮助这个MySQL查询。 理想情况下，我会使用node.js Sequelize ORM生成它。
这些表格是：
Questions: id, question Answers: id, question_id, answer 我的续集代码是：
models.questions.findAll({ where: { id: { $notIn: not_in } }, order: [['id','ASC'], [models.answers, 'id', 'ASC']], attributes: ['id', 'question'], include: [{ model: models.answers, attributes: ['id', 'question_id', 'answer'], }] })
将not_in设置为-1 ，Sequelize会生成以下查询：
SELECT `questions`.`id`, `questions`.`question`, `answers`.`id` AS `answers.id`, `answers`.`question_id` AS `answers.question_id`, `answers`.`answer` AS `answers.answer` FROM `questions` AS `questions` LEFT OUTER JOIN `answers` AS `answers` ON `questions`.`id` = `answers`.`question_id` WHERE `questions`.`id` NOT IN ( -1 ) ORDER BY `questions`.`id` ASC, `answers`.`id` ASC
结果在：
id | question | answers.id | answers.question_id | answers.answer 13 | first question | 17 | 13 | 1st answer 13 | first question | 23 | 13 | 2nd answer 13 | first question | 24 | 13 | 3rd answer 14 | second question | 18 | 14 | 1st answer 14 | second question | 21 | 14 | 2nd answer 14 | second question | 22 | 14 | 3rd answer 15 | third question | 19 | 15 | 1st answer 15 | third question | 20 | 15 | 2nd answer
我想这个结果，但随机sorting的问题。
所以，而不是13,14和15，它可能是answers.id ，但答案仍然与他们的问题alignment，并按answers.idsorting。
希望任何指针的Sequelize代码或MySQL查询来获得这样的结果。 谢谢！
我已经尝试在各个地方添加ORDER BY RAND() ，但最终还是要洗牌。
PS另外，以前我只需要随机挑选一个问题就可以了，我使用了这个问题：
SELECT `questions`.`id` AS `question_id`, `questions`.`question` AS `question`, `answers`.`id` AS `answer_id`, `answers`.`answer` AS `answer` FROM (SELECT `questions`.`id`, `questions`.`question` FROM `questions` AS `questions` WHERE (SELECT `question_id` FROM `answers` AS `answers` WHERE `questions`.`id` = `answers`.`question_id` AND questions.id NOT IN ( -1 ) LIMIT 1) IS NOT NULL ORDER BY RAND() LIMIT 1) AS `questions` INNER JOIN `answers` AS `answers` ON `questions`.`id` = `answers`.`question_id` ORDER BY `answers`.`question_id`, `answers`.`id`
哪个会返回，例如：
id | question | answers.id | answers.question_id | answers.answer 14 | second question | 18 | 14 | 1st answer 14 | second question | 21 | 14 | 2nd answer 14 | second question | 22 | 14 | 3rd answer
在普通的MySQL中：
SELECT ... FROM ( SELECT RAND() AS rnd, id FROM questions ) AS r JOIN questions AS q ON q.id = r.id JOIN answers AS a ON a.question_id = q.id ORDER BY r.rnd, a.id