MySQL查询10表（Sequelize或原始查询）

为了返回下面的JSON示例，我们需要查询10个表，同时查找两个表之间的值。 我的SQL知识是有限的，所以我们在这里寻求帮助。

JSON：

{ project: 1, name: "BluePrint1", description: "BluePrint 1 Description", listWorkPackages: [ { id: 1, name: "WorkPackage 1 Name", description: "WorkPackage 1 Description", type: "WorkPackage Type", department: "WorkPackage Department", status: "Workpackage work status" }, { id: 2, name: "WorkPackage 2 Name", description: "WorkPackage 2 Description", type: "WorkPackage Type", department: "WorkPackage Department", status: "Workpackage work status" } ], assignments: [ { id: 3, name: "WorkPackage 3 Name", description: "WorkPackage 3 Description", type: "WorkPackage Type", department: "WorkPackage Department", status: "Workpackage work status" } ] } 

数据库：

数据库看起来像这样（ 更多细节在新标签中打开） ：

逻辑：

使用WorkerID，我们希望所有的WorkPackages ：

• 与工人具有相同的types ;
• 属于同一部门 ;
• 也是直接分配的 （ 通过表WA_Assignments ）

所以我们可以发送JSON上的信息，我们需要查看这10个表格：

1. WK_Worker
2. WT_WorkerType
3. TY_Type
4. WP_WorkPackage
5. WE_WorkPackageExecution
6. WS_WorkStatus
7. BL_Blueprint
8. PR_Project
9. DP_Department
10. WA_WorkAssignments

我的问题：

我对SQL的了解仅限于JOIN：

 SELECT * FROM BL_Blueprint JOIN PR_Project ON BL_idBlueprint = PR_idBlueprint JOIN WP_WorkPackage ON BL_idBlueprint = WP_idBlueprint JOIN WE_WorkPackageExecution ON WE_idWorkPackage = WP_idWorkPackage JOIN DP_Department ON WE_idDepartment = DP_idDepartment 

而且我们只需要search与Worker有相同types的工作包，但是我们只有在查看WT_WorkerType表之后才知道types。

我读了关于subquery哪里可以在WHERE字段中select，但不能得到我的头，并得到一个工作的查询。

问题：

最后，我的问题是：

1. SQL查询;

我使用Sequelize ，如果它可以帮助，但从文档我认为原始查询会更容易。

谢谢大家的帮助和支持。

---

解

所有的爱去@MihaiOvidiuDrăgoi（在评论），帮助我到达解决scheme

第一个 SELECT获取Assignments， 第二个则获得上面的逻辑。 标签有助于确定哪个是哪个，而我们为了缓解JSON的创build。

 SELECT * FROM ((SELECT BL_Name, BL_Description, WP_Name, WP_Description, PR_idProject, WE_idWorkPackageExecution, WE_idWorkStatus, TY_TypeName, TY_Description, WS_WorkStatus, DP_Name, DP_Description, 'second_select' FROM WK_Worker, WP_WorkPackage INNER JOIN BL_Blueprint ON BL_idBlueprint = WP_idBlueprint INNER JOIN PR_Project ON PR_idBlueprint = BL_idBlueprint INNER JOIN WE_WorkPackageExecution ON WE_idWorkPackage = WP_idWorkPackage AND WE_idProject = PR_idProject INNER JOIN WS_WorkStatus ON WS_idWorkStatus = WE_idWorkStatus INNER JOIN DP_Department ON DP_idDepartment = WE_idDepartment INNER JOIN WA_WorkAssignments ON WA_idWorkPackageExecution = WE_idWorkPackageExecution INNER JOIN TY_Type ON TY_idType = WP_idType WHERE WA_idWorker = 1 AND WK_idWorker = 1) UNION ALL (SELECT BL_Name, BL_Description, WP_Name, WP_Description, PR_idProject, WE_idWorkPackageExecution, WE_idWorkStatus, TY_TypeName, TY_Description, WS_WorkStatus, DP_Name, DP_Description, 'first_select' FROM WK_Worker, WP_WorkPackage JOIN BL_Blueprint ON BL_idBlueprint = WP_idBlueprint JOIN PR_Project ON PR_idBlueprint = BL_idBlueprint JOIN WE_WorkPackageExecution ON WE_idWorkPackage = WP_idWorkPackage AND WE_idProject = PR_idProject JOIN WS_WorkStatus ON WS_idWorkStatus = WE_idWorkStatus JOIN DP_Department ON DP_idDepartment = WE_idDepartment JOIN TY_Type ON TY_idType = WP_idType WHERE WK_idWorker = 1 AND DP_idDepartment IN (SELECT WK_idDepartment FROM WK_Worker WHERE WK_idWorker = 1) AND WP_idType IN (SELECT TY_idType FROM TY_Type JOIN WT_WorkerType ON TY_idType = WT_idType WHERE WT_idWorker = 1) ) ) AS T1 ORDER BY T1.PR_idProject 

Answer 1

既然你似乎需要一个由两个不同的连接组成的结果集，你应该做一些类似的事情

 SELECT * from ( SELECT 1 UNION ALL SELECT 2 ) a ORDER by ... 

你的select语句也应该包括逻辑名称作为不同的列（如“firstselect”） – 这样你就可以知道你的行是从哪里来的。

Answer 2

如果您想尝试使用sequelize进行子查询，则可以在部分查询中使用文字：

 User.findAll({ attributes: [ [sequelize.literal('SELECT ...'), 'subq'], ] }).then(function(users) { });