如何在mongoose中使用更多的$ group

[ { "_id":"56569bff5fa4f203c503c792", "Status":{ "StatusID":2, "StatusObjID":"56559aad5fa4f21ca8492277", "StatusValue":"Closed" }, "OwnerPractice":{ "PracticeObjID":"56559aad5fa4f21ca8492291", "PracticeValue":"CCC", "PracticeID":3 }, "Name":"AA" }, { "_id":"56569bff5fa4f203c503c792", "Status":{ "StatusID":2, "StatusObjID":"56559aad5fa4f21ca8492277", "StatusValue":"Open" }, "OwnerPractice":{ "PracticeObjID":"56559aad5fa4f21ca8492292", "PracticeValue":"K12", "PracticeID":2 }, "Name":"BB" } 

]

在上面的json响应中，

如何将PracticeValue，StatusValue分组为单个函数，

以下代码仅用于组态StatusValue，请帮助如何将相同function的实践值进行分组，

 Opp.aggregate([ {$group: { _id: '$Status.StatusValue', count: {$sum: 1} }} ], function (err, result) { res.send(result); }); 

我的回答是，

 [ { "_id":"Deleted", "count":0 }, { "_id":"Open", "count":1 }, { "_id":"Closed", "count":1 } ] please help me, how to use more then $group function.. 

Answer 1

你可以像这样分成多个字段：

 var resultAggr = {Status: [], Practice: []}; Opp.aggregate( [ {$group: { _id: '$Status.StatusValue', count: {$sum: 1} }} ], function (err, statusResult) { resultAggr.Status = statusResult; Opp.aggregate( [ {$group: { _id: '$OwnerPractice.PracticeValue', count: {$sum: 1} }} ], function (err, practiceResult) { resultAggr.Practice = practiceResult; res.send([resultAggr]) }); });