链接ES6承诺在mongoose与打字稿

我试图链接到Mongoose 4.5.4的 ES6承诺

public static signup(req: express.Request, res: express.Response) { UserModel.findOne({ email: req.body.email }).exec() .then(existingUser => { if(existingUser) { return res.send({ message: 'Email is in use' }); } return UserModel.create({ firstName: req.body.firstName, lastName: req.body.lastName, email: req.body.email, password: req.body.password }); }) .then(user => { return res.send({ token: AuthUtils.createJWT(user)}); }) .catch(err => { console.log(err); }); } 

但是，当我尝试return UserModel.create(...)时，Typescript会引发以下错误：

Argument of type '(existingUser: IUser & _Model<IUser> & EventEmitter) => Response | MongoosePromise<IUser & _Model...' is not assignable to parameter of type '(...args: (IUser & _Model<IUser> & EventEmitter)[]) => void | (IUser & _Model<IUser> & EventEmitt...'. Type 'Response | MongoosePromise<IUser & _Model<IUser> & EventEmitter>' is not assignable to type 'void | (IUser & _Model<IUser> & EventEmitter) | PromiseLike<IUser & _Model<IUser> & EventEmitter>'. Type 'Response' is not assignable to type 'void | (IUser & _Model<IUser> & EventEmitter) | PromiseLike<IUser & _Model<IUser> & EventEmitter>'. Type 'Response' is not assignable to type 'PromiseLike<IUser & _Model<IUser> & EventEmitter>'. Property 'then' is missing in type 'Response'.

.create()返回一个Promise，所以我不能看到这将是一个问题。

任何帮助，将不胜感激。

Answer 1

通过使用promise的响应中的existing标志，将控制stream添加到现有用户。 例：

 public static signup(req: express.Request, res: express.Response) { UserModel.findOne({ email: req.body.email }).exec() .then(existingUser => { if(existingUser) { return Promise.resolve({ user: existing, existing: true }); } return UserModel.create({ firstName: req.body.firstName, lastName: req.body.lastName, email: req.body.email, password: req.body.password }).then((user) => { return Promise.resolve({ existing: false, user: user }); }); }) .then(response => { if (response.existing) { return res.send({ message: `Email ${response.user.email} is in use` }); } else return res.send({ token: AuthUtils.createJWT(response.user)}); }) .catch(err => { console.log(err); }); } 

Answer 2

我实际上最终build立了我的ES6项目，以便我可以使用async/await

它使我能够大幅简化代码。

 public static async signup(req: express.Request, res: express.Response) { try { let user = await UserModel.findOne({ email: req.body.email }).exec() if(user) { throw `Email ${user.email} is in use`; } if(environment.debug) console.log(`Creating new user ${req.body.firstName} ${req.body.lastName} with email ${req.body.email}`); user = await UserModel.create({ firstName: req.body.firstName, lastName: req.body.lastName, email: req.body.email, password: req.body.password }); return res.send({ token: AuthUtils.createJWT(user)}); } catch(e) { console.log(e); res.send({ error: e }); } }